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The New Coffee Room

  1. TNCR
  2. General Discussion
  3. Puzzle time - the Fibonacci numbers

Puzzle time - the Fibonacci numbers

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  • jon-nycJ Online
    jon-nycJ Online
    jon-nyc
    wrote on last edited by jon-nyc
    #22

    No, the cycle length of Fib mod (2^n) = 3*2^(n-1))

    Check Fmod2, Fmod4, Fmod8, Fmod16 etc for their cycle lengths. You’ll get 3,6,12,24,48 etc. I’m wondering if it holds. I think it will.

    You were warned.

    1 Reply Last reply
    • KlausK Offline
      KlausK Offline
      Klaus
      wrote on last edited by
      #23

      Here's a list of pairs where the first number shows the "n" (but only for powers of 2) and the second one the associated cycle length. Maybe I missunderstood something but your conjecture doesn't seem to hold.

      [(2,6),(4,24),(8,60),(16,24),(32,36),(64,120),(128,420),(256,264),(512,516),(1024,72),(2048,600),(4096,1368),(8192,720)]
      
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      • jon-nycJ Online
        jon-nycJ Online
        jon-nyc
        wrote on last edited by jon-nyc
        #24

        But your original list is this one:

        (left side numbering mine, right side list yours)

        3e9774ed-e059-4cd4-956f-c8646a08d27b-image.png

        You were warned.

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        • KlausK Offline
          KlausK Offline
          Klaus
          wrote on last edited by
          #25

          Ah, looks like an "off by two" error somewhere. Hmm....

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          • KlausK Offline
            KlausK Offline
            Klaus
            wrote on last edited by Klaus
            #26

            Turned out to be two "off by 1" errors that have to do with indices starting at 0 and not 1.

            What about this result?

            [(2,3),(4,6),(8,12),(16,24),(32,48),(64,96),(128,192),(256,384),(512,768),(1024,1536),(2048,3072),(4096,6144),(8192,12288)]
            
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            • KlausK Offline
              KlausK Offline
              Klaus
              wrote on last edited by Klaus
              #27

              It looks like linear relations between the cycle length happen quite frequently. This is a scatter plot of the cycle lengths I computed above (haven't used R in a while - fun for plotting data!). Observe all the dotted lines. The points you identified are on one of those lines. Also interesting to see a few outliers.

              440d6f5b-c0a6-4d2d-b301-7d3d66c1fafd-image.png

              I have marked the points you are interested in in red. You see that there are way more points on that line.

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              • jon-nycJ Online
                jon-nycJ Online
                jon-nyc
                wrote on last edited by
                #28

                Interesting.

                So it turns out Fibonacci cycle lengths a thing people study. They’re called Pisano numbers and understanding them is really about understanding Pisano numbers for prime powers.

                A neat property is that if n and m are coprime then period(mn) is least common multiple of period(n) and period(m).

                You were warned.

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                • jon-nycJ Online
                  jon-nycJ Online
                  jon-nyc
                  wrote on last edited by
                  #29

                  Wait a minute, is that really your graph up there? This is from Wiki

                  396851CA-71EE-4E8B-AB14-42964B4121AC.png

                  You were warned.

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                  • KlausK Offline
                    KlausK Offline
                    Klaus
                    wrote on last edited by Klaus
                    #30

                    Yes, it's my graph. I haven't seen the WIki graph yet, but it shows the same data, so of course it's similar. It's an interesting coincidence that they also cut off at 10,000.

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                    • KlausK Offline
                      KlausK Offline
                      Klaus
                      wrote on last edited by
                      #31

                      Just for fun, here's the continuation of the dataset for cycle lengths up to 20000.

                      1549ea7c-ea85-4eca-aea0-3b73c980f9aa-image.png

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