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The New Coffee Room

  1. TNCR
  2. General Discussion
  3. Puzzle time - the Fibonacci numbers

Puzzle time - the Fibonacci numbers

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  • Doctor PhibesD Doctor Phibes

    Are you two about to have a 'my dick is smaller' contest?

    KlausK Offline
    KlausK Offline
    Klaus
    wrote on last edited by
    #19

    @Doctor-Phibes Did you know that dick sizes have a Fibonacci distribution? It's a distribution with a very long tail...

    <insert @George-K rimshot image macro here>

    1 Reply Last reply
    • jon-nycJ jon-nyc

      Interesting observation:

      Cycle lengths 2^n = 3*2^(n-1) at least within the first 100. Does that continue?

      jon-nycJ Online
      jon-nycJ Online
      jon-nyc
      wrote on last edited by
      #20

      @jon-nyc said in Puzzle time - the Fibonacci numbers:

      Interesting observation:

      Cycle lengths 2^n = 3*2^(n-1) at least within the first 100. Does that continue?

      bump for Klaus and his little 4 line program.

      Only non-witches get due process.

      • Cotton Mather, Salem Massachusetts, 1692
      KlausK 1 Reply Last reply
      • jon-nycJ jon-nyc

        @jon-nyc said in Puzzle time - the Fibonacci numbers:

        Interesting observation:

        Cycle lengths 2^n = 3*2^(n-1) at least within the first 100. Does that continue?

        bump for Klaus and his little 4 line program.

        KlausK Offline
        KlausK Offline
        Klaus
        wrote on last edited by Klaus
        #21

        @jon-nyc said in Puzzle time - the Fibonacci numbers:

        @jon-nyc said in Puzzle time - the Fibonacci numbers:

        Interesting observation:

        Cycle lengths 2^n = 3*2^(n-1) at least within the first 100. Does that continue?

        bump for Klaus and his little 4 line program.

        Can you explain? You mean that the cycle length of Fib mod (2^n) is the same as Fib mod (3*2^(n-1))? That doesn't seem to be true.

        I uploaded the first 10,000 cycle lengths here, if you want to check this yourself.
        https://www.heypasteit.com/clip/0IV18W

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        • jon-nycJ Online
          jon-nycJ Online
          jon-nyc
          wrote on last edited by jon-nyc
          #22

          No, the cycle length of Fib mod (2^n) = 3*2^(n-1))

          Check Fmod2, Fmod4, Fmod8, Fmod16 etc for their cycle lengths. You’ll get 3,6,12,24,48 etc. I’m wondering if it holds. I think it will.

          Only non-witches get due process.

          • Cotton Mather, Salem Massachusetts, 1692
          1 Reply Last reply
          • KlausK Offline
            KlausK Offline
            Klaus
            wrote on last edited by
            #23

            Here's a list of pairs where the first number shows the "n" (but only for powers of 2) and the second one the associated cycle length. Maybe I missunderstood something but your conjecture doesn't seem to hold.

            [(2,6),(4,24),(8,60),(16,24),(32,36),(64,120),(128,420),(256,264),(512,516),(1024,72),(2048,600),(4096,1368),(8192,720)]
            
            1 Reply Last reply
            • jon-nycJ Online
              jon-nycJ Online
              jon-nyc
              wrote on last edited by jon-nyc
              #24

              But your original list is this one:

              (left side numbering mine, right side list yours)

              3e9774ed-e059-4cd4-956f-c8646a08d27b-image.png

              Only non-witches get due process.

              • Cotton Mather, Salem Massachusetts, 1692
              1 Reply Last reply
              • KlausK Offline
                KlausK Offline
                Klaus
                wrote on last edited by
                #25

                Ah, looks like an "off by two" error somewhere. Hmm....

                1 Reply Last reply
                • KlausK Offline
                  KlausK Offline
                  Klaus
                  wrote on last edited by Klaus
                  #26

                  Turned out to be two "off by 1" errors that have to do with indices starting at 0 and not 1.

                  What about this result?

                  [(2,3),(4,6),(8,12),(16,24),(32,48),(64,96),(128,192),(256,384),(512,768),(1024,1536),(2048,3072),(4096,6144),(8192,12288)]
                  
                  1 Reply Last reply
                  • KlausK Offline
                    KlausK Offline
                    Klaus
                    wrote on last edited by Klaus
                    #27

                    It looks like linear relations between the cycle length happen quite frequently. This is a scatter plot of the cycle lengths I computed above (haven't used R in a while - fun for plotting data!). Observe all the dotted lines. The points you identified are on one of those lines. Also interesting to see a few outliers.

                    440d6f5b-c0a6-4d2d-b301-7d3d66c1fafd-image.png

                    I have marked the points you are interested in in red. You see that there are way more points on that line.

                    1 Reply Last reply
                    • jon-nycJ Online
                      jon-nycJ Online
                      jon-nyc
                      wrote on last edited by
                      #28

                      Interesting.

                      So it turns out Fibonacci cycle lengths a thing people study. They’re called Pisano numbers and understanding them is really about understanding Pisano numbers for prime powers.

                      A neat property is that if n and m are coprime then period(mn) is least common multiple of period(n) and period(m).

                      Only non-witches get due process.

                      • Cotton Mather, Salem Massachusetts, 1692
                      1 Reply Last reply
                      • jon-nycJ Online
                        jon-nycJ Online
                        jon-nyc
                        wrote on last edited by
                        #29

                        Wait a minute, is that really your graph up there? This is from Wiki

                        396851CA-71EE-4E8B-AB14-42964B4121AC.png

                        Only non-witches get due process.

                        • Cotton Mather, Salem Massachusetts, 1692
                        1 Reply Last reply
                        • KlausK Offline
                          KlausK Offline
                          Klaus
                          wrote on last edited by Klaus
                          #30

                          Yes, it's my graph. I haven't seen the WIki graph yet, but it shows the same data, so of course it's similar. It's an interesting coincidence that they also cut off at 10,000.

                          1 Reply Last reply
                          • KlausK Offline
                            KlausK Offline
                            Klaus
                            wrote on last edited by
                            #31

                            Just for fun, here's the continuation of the dataset for cycle lengths up to 20000.

                            1549ea7c-ea85-4eca-aea0-3b73c980f9aa-image.png

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