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The New Coffee Room

  1. TNCR
  2. General Discussion
  3. Puzzle time - the Triangle

Puzzle time - the Triangle

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  • jon-nycJ Offline
    jon-nycJ Offline
    jon-nyc
    wrote on last edited by jon-nyc
    #1

    A teacher (lets call him Klaus) used to give this problem as part of his elementary geometry class:

    A right triangle has hypotenuse (BC) of length 10, and a height (AP) of length 6. What is the area?

    5C5B3817-9600-458A-8DCB-B097BB0A4362.jpeg

    His average students (lets call them Horace and Ax) got full credit for the answer 1/2 * 10 * 6 = 30.

    But a really smart kid (lets call her Taiwan girl) couldn’t solve the problem.

    Why not?

    "You never know what worse luck your bad luck has saved you from."
    -Cormac McCarthy

    1 Reply Last reply
    • AxtremusA Away
      AxtremusA Away
      Axtremus
      wrote on last edited by Klaus
      #2

      :::

      There are three hypothenuses. Which one has the length 10?

      :::

      1 Reply Last reply
      • KlausK Offline
        KlausK Offline
        Klaus
        wrote on last edited by
        #3

        :::

        Is it something as boring as "it isn't specified that AP is the height, so it could be something slightly different"?

        :::

        1 Reply Last reply
        • jon-nycJ Offline
          jon-nycJ Offline
          jon-nyc
          wrote on last edited by
          #4

          @Axtremus BC has length 10

          @Klaus AP is the height.

          "You never know what worse luck your bad luck has saved you from."
          -Cormac McCarthy

          1 Reply Last reply
          • KlausK Offline
            KlausK Offline
            Klaus
            wrote on last edited by Klaus
            #5

            Oh, now I see.

            :::

            AB isn't the hypotenuse.

            :::

            1 Reply Last reply
            • jon-nycJ Offline
              jon-nycJ Offline
              jon-nyc
              wrote on last edited by
              #6

              Nope that was just a typo on my part when I went back to clarify!

              "You never know what worse luck your bad luck has saved you from."
              -Cormac McCarthy

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              • kluursK Offline
                kluursK Offline
                kluurs
                wrote on last edited by kluurs
                #7

                ||AC represents the height - as the triangle is inverted for triangle CAB. 6 is the height of triangle PAB. ||

                1 Reply Last reply
                • AxtremusA Away
                  AxtremusA Away
                  Axtremus
                  wrote on last edited by
                  #8

                  :::

                  I was trying to say that the “really smart” kid cannot solve the problem because of the ambiguity stemming from there having three possible right triangles in the diagram: ABC, ACP, ABP. So when you say something like the hypothenuse has length 10, it’s ambiguous whether you’re referring to which hypothenuse, AB, AC, or BC.

                  :::

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                  • NunataxN Offline
                    NunataxN Offline
                    Nunatax
                    wrote on last edited by
                    #9

                    :::

                    Too lazy to look up the required formulas right now, but with A fixed as a right angle and CB equal to 10, height AP will be confined to a certain range. I guess it's at its maximum when angles C and B are both 45 degrees and even then AP will likely be less than 6? If that's the case, the scenario is simply impossible.

                    :::

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                    • jon-nycJ Offline
                      jon-nycJ Offline
                      jon-nyc
                      wrote on last edited by jon-nyc
                      #10

                      I should have named the smart kid Nunatax.

                      The triangle is impossible as this simple diagram shows us:

                      ED5C7B88-5A4F-4177-B4A3-861F6FEDAA50.jpeg

                      (Recall that, if the angle CAB is a right angle, it must lie on the perimeter of the circle, per Euclid

                      The maximum height of AP is 5.

                      "You never know what worse luck your bad luck has saved you from."
                      -Cormac McCarthy

                      taiwan_girlT 1 Reply Last reply
                      • KlausK Offline
                        KlausK Offline
                        Klaus
                        wrote on last edited by Klaus
                        #11

                        Nice!

                        I wonder what that restriction (of the maximal height) looks like in non-Euclidean geometries.

                        1 Reply Last reply
                        • MikM Offline
                          MikM Offline
                          Mik
                          wrote on last edited by
                          #12

                          The original formula would only work if CAB was a right triangle anyway, or 1/2 a rectangle.

                          “I am fond of pigs. Dogs look up to us. Cats look down on us. Pigs treat us as equals.” ~Winston S. Churchill

                          1 Reply Last reply
                          • jon-nycJ jon-nyc

                            I should have named the smart kid Nunatax.

                            The triangle is impossible as this simple diagram shows us:

                            ED5C7B88-5A4F-4177-B4A3-861F6FEDAA50.jpeg

                            (Recall that, if the angle CAB is a right angle, it must lie on the perimeter of the circle, per Euclid

                            The maximum height of AP is 5.

                            taiwan_girlT Offline
                            taiwan_girlT Offline
                            taiwan_girl
                            wrote on last edited by
                            #13

                            @jon-nyc said in Puzzle time - the Triangle:

                            I should have named the smart kid Nunatax.

                            Correct, you should not have picked me! 555

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