Puzzle time - who’s bullet?
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I will think some more. Should not be too difficult. Lol
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||spoiler||
Both hit - chance is .75 x .25 = .1875
Both miss - chance is .25 x .75 = .1875
J hit, K miss - chance is .75 x .75 = .5625
J miss, K hit - chance is .25 x .25 = .0625If one bullet hits, either case 3 or 4 has taken place. Chance it was Jon is .5625/(.5625+.0625) = 90%.
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@Doctor-Phibes your spoiler didn’t work. LOL
but what you did makes sense. I am going to claim that I would have done the same answer.
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Bugger, sorry.
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@Doctor-Phibes said in Puzzle time - who’s bullet?:
Bugger, sorry.
Don't be sorry. You are t3h stats jock!
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@taiwan_girl said in Puzzle time - who’s bullet?:
@jon-nyc #1 and #2 cannot happen. In the riddle, one bullet hits you said. I think that leaves only 3 and 4
Well it’s an intermediate step which allows you to get to the conditional probability that the target is hit by only one bullet.
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To make the problem more realistic instead of shooting a target the puzzle should have been successfully playing a Rachmaninoff etude.
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What's the probability of somebody's family member shooting either Klaus or Jon as they attempt to play a Rachmaninoff etude?
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Fucking IT people.
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I have a similar puzzle for Jon.
Jon sends us a recording of a Rachmaninoff etude and tells us that it is a recording from him.
Jon is a trustworthy forum member, so before listening we are 99% confident that Jon tells the truth and didn't actually send us a recording by Klaus (which would be flawless).
However, we also know that the probability that Jon hits a correct note is only 40%.
We start listening to the 10 first notes. They are all correct.
What's the likelihood that it is indeed Jon's recording?
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100.0%