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The New Coffee Room

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  3. Puzzle time - penalty kicks

Puzzle time - penalty kicks

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  • jon-nycJ Offline
    jon-nycJ Offline
    jon-nyc
    wrote on last edited by jon-nyc
    #10

    Lets do some arithmetic. We're looking for an 'a' and 'b' such that:

    a/b<4/5
    (a+1)/(b+1)>4/5

    The first equation simplifies to:
    5a<4b

    The second simplifies to:
    5a+1>4b.

    So 5a+1 > 4b > 5a.

    But that can't be true for positive integers a and b. So the answer is you can't skip 80%.

    Ax notices some other numbers you can't skip. He noticed that 90%, 50% have the same property.

    Can you generalize the property?

    "You never know what worse luck your bad luck has saved you from."
    -Cormac McCarthy

    taiwan_girlT 1 Reply Last reply
    • jon-nycJ jon-nyc

      Lets do some arithmetic. We're looking for an 'a' and 'b' such that:

      a/b<4/5
      (a+1)/(b+1)>4/5

      The first equation simplifies to:
      5a<4b

      The second simplifies to:
      5a+1>4b.

      So 5a+1 > 4b > 5a.

      But that can't be true for positive integers a and b. So the answer is you can't skip 80%.

      Ax notices some other numbers you can't skip. He noticed that 90%, 50% have the same property.

      Can you generalize the property?

      taiwan_girlT Offline
      taiwan_girlT Offline
      taiwan_girl
      wrote on last edited by
      #11

      @jon-nyc said in Puzzle time - penalty kicks:

      Can you generalize the property?

      Yes, if you divide two integers (with the numerator smaller than the denominator) and you continually increase both by 1, you will eventually have the answer equal 0.5, 0.8, and 0.9!!

      5555

      1 Reply Last reply
      • jon-nycJ Offline
        jon-nycJ Offline
        jon-nyc
        wrote on last edited by
        #12

        Yes you will, but what other percentages are unavoidable if you start below them and end above them?

        "You never know what worse luck your bad luck has saved you from."
        -Cormac McCarthy

        1 Reply Last reply
        • AxtremusA Offline
          AxtremusA Offline
          Axtremus
          wrote on last edited by
          #13

          :::

          Let's see ...

          From:
          a/b < A/B AND (a+1)/(b+1) > A/B

          We get to Ba + (B-A) > Ab > B*a

          If we are talking only natural numbers, the condition boils down to (B-A) = 1.

          So fractions like 1/2 (50%), 2/3 (66.666...%), 3/4 (75%), 4/5 (80%), ... 9/10 (90%) ... all fractions that can be written as X/(X+1) are "special" that way.

          :::

          1 Reply Last reply
          • jon-nycJ Offline
            jon-nycJ Offline
            jon-nyc
            wrote on last edited by
            #14

            Ax got it!

            "You never know what worse luck your bad luck has saved you from."
            -Cormac McCarthy

            1 Reply Last reply
            • jon-nycJ Offline
              jon-nycJ Offline
              jon-nyc
              wrote on last edited by
              #15

              When I first saw this problem last week I thought it was stupid and the answer was obviously “of course you can skip 80”. I didn’t even sit down to play with it for a few days.

              "You never know what worse luck your bad luck has saved you from."
              -Cormac McCarthy

              1 Reply Last reply
              • AxtremusA Offline
                AxtremusA Offline
                Axtremus
                wrote on last edited by
                #16

                FWWI, @Klaus might be happy to know that this puzzle got me to install Haskell. 😄

                KlausK 1 Reply Last reply
                • AxtremusA Axtremus

                  FWWI, @Klaus might be happy to know that this puzzle got me to install Haskell. 😄

                  KlausK Offline
                  KlausK Offline
                  Klaus
                  wrote on last edited by Klaus
                  #17

                  @axtremus said in Puzzle time - penalty kicks:

                  FWWI, @Klaus might be happy to know that this puzzle got me to install Haskell. 😄

                  There are infinitely many good reasons to install Haskell, but if all you want is list comprehensions, then you can do the same thing in many other languages, such as Python.

                  b01503f1-6c8e-42c7-8f8e-347b6f929f17-image.png

                  In Haskell you can of course write the program in a cooler and more general way using monads.

                  import Control.Monad
                  [1..500] >>= \x -> [1..500] >>= \y -> guard (x/y < 0.8 && (x+1)/(y+1) > 0.8) >> return (x,y)
                  
                  1 Reply Last reply
                  • jon-nycJ Offline
                    jon-nycJ Offline
                    jon-nyc
                    wrote on last edited by
                    #18

                    I’m a little sad nobody commented on “Diego Primadona”.

                    "You never know what worse luck your bad luck has saved you from."
                    -Cormac McCarthy

                    1 Reply Last reply
                    • AxtremusA Offline
                      AxtremusA Offline
                      Axtremus
                      wrote on last edited by
                      #19

                      I have read @Klaus mentioning Haskell a few times in the past, and has been meaning to check it out. This puzzle is just the thing that finally got me to do. These days my primary computer programming language seems to be “go” (or “golang”), mostly because I found it quite convenient for dealing with web APIs.

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