Puzzle time - Beetles edition
-
Oh, now I see. You mean they constantly change direction to take the shortest path to the next beetle, whereever that beetle is at that time, right? But they do not "foresee" the future movement of that other beetle to adapt their "shortest path" calculation, right?
That sounds like a hard puzzle.
-
I also wonder about the limit case: infinite number of beetles on a circle. I'd say the solution is that no traveling occurs and they don't meet in the middle. But for finite n it seems to be the case that they would meet in the middle. That's a strange discontinuity.
-
:::
OK, slightly more seriously:
I'd say the beetles will always form a square at each point in time, but that square rotates and shrinks.
At every time, the movement vectors will hence be orthogonal to each other. Which means that every beetle has to move distance s before the size of the square becomes 0.
:::
-
@Klaus said in Puzzle time - Beetles edition:
But then the "orthogonality" thing doesn't hold anymore and things get complicated. Please don't tell me you want me to write down some complicated trigonometric functions and differential equations!
I didn't have to.
-
@Klaus said in Puzzle time - Beetles edition:
Also, bonus question for Jon:
How many times do the beetles spin around each other before they meet?
Define 'spin around each other'. You mean that the square formed by the four of them rotates 360 degrees?
-
@Klaus said in Puzzle time - Beetles edition:
But then the "orthogonality" thing doesn't hold anymore and things get complicated. Please don't tell me you want me to write down some complicated trigonometric functions and differential equations!
I could give you a hint. Really a way to reframe the orthogonality that will generalize to other n