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The New Coffee Room

  1. TNCR
  2. General Discussion
  3. Puzzle time - integers

Puzzle time - integers

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  • KlausK Offline
    KlausK Offline
    Klaus
    wrote on last edited by
    #2

    None of the conditions you specify says something about numbers not in S, so there's no way to say something about numbers not in S.

    Presumably you meant to say that S is the smallest set that is closed under the application of these rules?

    1 Reply Last reply
    • jon-nycJ Offline
      jon-nycJ Offline
      jon-nyc
      wrote on last edited by
      #3

      I considered adding the word smallest and thought ‘no one here will be such a putz to pretend not to understand’

      Only non-witches get due process.

      • Cotton Mather, Salem Massachusetts, 1692
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      • KlausK Offline
        KlausK Offline
        Klaus
        wrote on last edited by
        #4

        I'm happy to help 🙂

        There are many such definitions where you want something different from "smallest" (e.g. coinductive definitions).

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        • KlausK Offline
          KlausK Offline
          Klaus
          wrote on last edited by Klaus
          #5

          1 is not in S.

          (note that you didn't ask for an exhaustive list of those not in S 😉 )

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          • KlausK Offline
            KlausK Offline
            Klaus
            wrote on last edited by
            #6

            ...and if you want the complete set:

            It's the set of positive integers minus S.

            Which is a perfectly valid mathematical definition of the integers not in S.

            So presumably you want us to specify that set in a particular way?

            😉

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            • jon-nycJ Offline
              jon-nycJ Offline
              jon-nyc
              wrote on last edited by
              #7

              Ha

              Only non-witches get due process.

              • Cotton Mather, Salem Massachusetts, 1692
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              • KlausK Offline
                KlausK Offline
                Klaus
                wrote on last edited by Klaus
                #8

                :::

                Obviously, when a number n is in S, then n+5 must also be in S.

                So once we have all digits from 0 to 4 (or 5 to 9) as last digits of numbers, all numbers above it must be in S.

                So the question is whether we ever get all last digits.

                I think we can get to all last-digits except 0 and 5, since any number that ends with 0 or 5 squared also ends with 0 or 5.

                So, my theory about the positive integers not in S is:

                There's some noise in the beginning, and after a while it's only the numbers that end with 0 or 5.

                :::

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                • jon-nycJ Offline
                  jon-nycJ Offline
                  jon-nyc
                  wrote on last edited by
                  #9

                  :::

                  On the right track but not quite there

                  :::

                  Only non-witches get due process.

                  • Cotton Mather, Salem Massachusetts, 1692
                  1 Reply Last reply
                  • KlausK Offline
                    KlausK Offline
                    Klaus
                    wrote on last edited by
                    #10

                    So you are saying my last statement is wrong, or are you saying it's not precise enough?

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                    • jon-nycJ Offline
                      jon-nycJ Offline
                      jon-nyc
                      wrote on last edited by
                      #11

                      Depends on how one defines ‘noise‘. But what I really mean is “from what I infer from your words you’re still missing an insight here”

                      Only non-witches get due process.

                      • Cotton Mather, Salem Massachusetts, 1692
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                      • KlausK Offline
                        KlausK Offline
                        Klaus
                        wrote on last edited by
                        #12

                        OK, here's a precise version of the statement:

                        :::

                        There is a number N, such that for all n >N, n is not in S if and only if the last digit of n is 0 or 5.

                        :::

                        Is that correct?

                        1 Reply Last reply
                        • jon-nycJ Offline
                          jon-nycJ Offline
                          jon-nyc
                          wrote on last edited by jon-nyc
                          #13

                          Yes but tell me N. You’re missing something or you would know what N is.

                          Only non-witches get due process.

                          • Cotton Mather, Salem Massachusetts, 1692
                          1 Reply Last reply
                          • KlausK Offline
                            KlausK Offline
                            Klaus
                            wrote on last edited by Klaus
                            #14

                            N is smaller than or equal to 2915. Now don't tell me you want me to worry about selecting a particular number between 1 and 2915!!!

                            1 Reply Last reply
                            • jon-nycJ Offline
                              jon-nycJ Offline
                              jon-nyc
                              wrote on last edited by
                              #15

                              Yes I do.

                              Only non-witches get due process.

                              • Cotton Mather, Salem Massachusetts, 1692
                              1 Reply Last reply
                              • jon-nycJ Offline
                                jon-nycJ Offline
                                jon-nyc
                                wrote on last edited by
                                #16

                                What Klaus missed:

                                :::

                                The only ‘noise’ (besides all multiples of 5) is the number 1.

                                • 2 is granted which gets you all numbers ending in 2 or 7.
                                • 7^2 is 49 which gets you all the numbers ending in 9 and 4 above that
                                • after 49 is 54. 54^2 is 3136 which gets you all the numbers ending in 6 or 1 above it.
                                  BUT
                                • once you have the *6s, you’ll get to 6^8 which gets you back to 6 and 11, etc.
                                • that gets you to 16 which gets you back to 4 and 9
                                • that 9 gets you back to 3 and 8

                                So we have 2,3,4,6,7,8,9 covered plus any number that is a multiple of 5 above them.

                                So only 1 is missing, along with all multiples of 5

                                :::

                                Only non-witches get due process.

                                • Cotton Mather, Salem Massachusetts, 1692
                                1 Reply Last reply
                                • KlausK Offline
                                  KlausK Offline
                                  Klaus
                                  wrote on last edited by
                                  #17

                                  Nice!

                                  54^2 is 2916 and not 3136, though - that was the source of the 2915 bound I was giving above. So my bound was pointing in the right direction 🙂

                                  1 Reply Last reply
                                  • jon-nycJ Offline
                                    jon-nycJ Offline
                                    jon-nyc
                                    wrote on last edited by
                                    #18

                                    My math buddy at CS pointed out that Fermat’s Little Theorem could help here too rather than finding actual paths back to the lower numbers.

                                    Only non-witches get due process.

                                    • Cotton Mather, Salem Massachusetts, 1692
                                    1 Reply Last reply
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